How do you compute $- 80 + 102$ $-80+102$ ?

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Answer 1 · 2016-10-23T07:28:39

$+ 22$ $+22$

Adding integers with different sign :
$- 80$ $color(blue)-80$ negative integer
and
$+ 102$ $color(red)+102$ positive integer

In this case we :
First subtract $102 - 80 = 22$ $color(green)(102-80=22)$
Second take sign of the greater
So,

$- 80 + 102 = + 22$ $color(blue)-80color(red)+102=color(red)+color(green)22$

How do you compute -80+102−80+102-80+102?