How do you condense $2/3ln y + ln t – ln y -1/2 ln t$ ?

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Answer 1 · 2016-09-02T01:27:13

$2/3lny+lnt-lny-1/2lnt=ln(sqrtt/(root(3)y))$

$2/3lny+lnt-lny-1/2lnt$

= $lny(2/3-1)+lnt(1-1/2)$

= $-1/3lny+1/2lnt$

Now as $1/mlna=lna^(1/m)=lnroot(m)a$ and $-lnb=ln(1/b)$

$-1/3lny+1/2lnt$

= $ln(1/root(3)y)+lnsqrtt$

= $ln(sqrtt/(root(3)y))$

How do you condense 2/3ln y + ln t – ln y -1/2 ln t2/3ln y + ln t – ln y -1/2 ln t?