How do you condense $2(ln)X + 1/2(ln)Y$ ?

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Answer 1 · 2016-05-08T06:40:32

$2lnX+1/2lnY=lnX^2*sqrtY$

$2lnX+1/2lnY$

= $lnX^2+lnY^(1/2)$ (as $nlna=lna^n$ )

= $lnX^2*Y^(1/2)$

= $lnX^2*sqrtY$

How do you condense 2(ln)X + 1/2(ln)Y2(ln)X + 1/2(ln)Y?