Question

How do you condense `2ln6 - ln3`?

Answer 1

`ln(12)`

Explanation:

Logs are subtracted if the source numbers are divided.

If the source number is raised to a power than you can multiply the loge by the value of that power. Suppose you had `log(x^a)` then this could be written as `alog(x)`

So `2ln(6)-ln(3)" " ->" " ln(6^2)-ln(3)" " ->" " ln(6^2/3)`

`=ln(12)`