How do you condense $2lnx+ln3$ ?

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Answer 1 · 2016-08-06T21:32:05

$ln(3x^2)$

If the logs are being added, the numbers are being multiplied.

$2lnx + ln 3 =lnx^2 + ln3$

= $ln(x^2 xx 3)$

= $ln(3x^2)$

How do you condense 2lnx+ln32lnx+ln3?