How do you condense $4 ln x + 3 ln y$ $4 ln x + 3 ln y$ ?

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Answer 1 · 2016-06-14T12:41:25

$4 ln x + 3 ln y = ln (x^{4} y^{3})$ $4lnx+3lny=ln(x^4y^3)$

Using $p {log}_{a} m = {log}_{a} m^{p}$ $plog_am=log_am^p$ and $log a + log b - log c = log (\frac{a b}{c})$ $loga+logb-logc=log((ab)/c)$

$4 ln x + 3 ln y$ $4lnx+3lny$

= ${ln x}^{4} + {ln y}^{3}$ $lnx^4+lny^3$

= $ln (x^{4} y^{3})$ $ln(x^4y^3)$

How do you condense 4lnx+3lny4 ln x + 3 ln y?