How do you condense $4ln2$ ?

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Answer 1 · 2018-05-31T00:58:46

$ln16$

The key realization here is that we can use the logarithm property

$alnb=ln(b^a)$

Where the coefficient on $ln$ becomes the exponent.

In our case, $a=4$ and $b=2$ . We can rewrite $4ln2$ as

$ln(2^4)$

which can be further simplified as

$ln16$

Hope this helps!

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