How do you condense $a ln 4 - ln b$ ?

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Answer 1 · 2016-04-14T08:29:04

$aln4-lnb=ln(4^a/b)$

We can condense using identities

$log_ap_1+log_ap_2+log_ap_3+..+log_ap_n=log_a(p_1*p_2*p_3*...*p_n)$

$log_ap-log_aq=log_a(p/q)$

$nlog_ap=log_ap^n$ and

$1/mlog_ap=log_ap^(1/m)=log_aroot(m)p$

Using these $aln4-lnb=ln4^a-lnb=ln(4^a/b)$

How do you condense a ln 4 - ln ba ln 4 - ln b?