How do you condense $ln(1+x^9)+1/2(ln(x)-ln(sin(x)$ ?

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Answer 1 · 2016-09-14T19:12:16

$ln(1+x^9)+1/2lnx-ln(sinx)=(1+x^9)/(2sinx)$

Use the following 2 laws of logs :

$logAB=logA+logB$

$log(A/B)=logA-logB$

to get :

$ln(1+x^9)+1/2lnx-ln(sinx)=(1/2(1+x^9))/sinx$

How do you condense ln(1+x^9)+1/2(ln(x)-ln(sin(x) ln(1+x^9)+1/2(ln(x)-ln(sin(x) ?