How do you condense ln z - 3 ln xlnz−3lnx?

1 Answer
Gió
May 6, 2016

I thought this:

Explanation:

We can start by writing the 33 as exponent of the argument of the second log:
lnz-lnx^3=lnz−lnx3=
ad then we condense the subtraction as a division of arguments:
=ln(z/x^3)=ln(zx3)
This is the best I got!

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