How do you condense $ln3+1/3ln(4 - x^2) - ln x$ ?

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Answer 1 · 2016-07-16T21:27:02

= $ln[(3(4 - x^2)^(1/3))/x]$ or it can be written as

$ln[(3xxroot(3)(4 - x^2))/x]$

If logs are added, the numbers are multiplied.
If logs are subtracted, the numbers are divided.

$ln3+1/3ln(4 - x^2) - ln x$

= $ln3+ln(4 - x^2)^(1/3) - ln x " power law"$

= $ln[(3(4 - x^2)^(1/3))/x]$

or it can be written as

$ln[(3xxroot(3)(4 - x^2))/x]$

How do you condense ln3+1/3ln(4 - x^2) - ln x ln3+1/3ln(4 - x^2) - ln x ?