How do you condense $ln5/2+ln6/2+ln7/2$ ?

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Answer 1 · 2016-12-04T19:58:09

Using the exponential logarithm rule, $alogb=logb^a$ , $ln5/2+ln6/2+ln7/2$ can be written as

$ln5^(1/2)+ln6^(1/2)+ln7^(1/2)=lnsqrt5+lnsqrt6+lnsqrt7$

Using the logarithmic multiplication rule, $loga+logb=logab$ , $lnsqrt5+lnsqrt6+lnsqrt7=lnsqrt210$

How do you condense ln5/2+ln6/2+ln7/2ln5/2+ln6/2+ln7/2?