How do you condense $ln v + 4 ln w + \frac{ln u}{3}$ $lnv+4lnw+lnu/3$ ?

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How do you condense $ln v + 4 ln w + \frac{ln u}{3}$ $lnv+4lnw+lnu/3$ ?

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Answer 1 · 2018-07-01T09:53:55

$ln (v w^{4} u^{\frac{1}{3}})$ $ln(vw^4u^(1/3))$

Explanation:

$using the laws of logarithms$ $"using the "color(blue)"laws of logarithms"$

$∙ x {log x}^{n} \Leftrightarrow n log x$ $•color(white)(x)logx^nhArrnlogx$

$∙ x log x + log y \Leftrightarrow log (x y)$ $•color(white)(x)logx+logyhArrlog(xy)$

$ln v + {ln w}^{4} + \frac{1}{3} ln u$ $lnv+lnw^4+1/3lnu$

$= ln v + {ln w}^{4} + {ln u}^{\frac{1}{3}}$ $=lnv+lnw^4+lnu^(1/3)$

$= ln (v w^{4} u^{\frac{1}{3}})$ $=ln(vw^4u^(1/3))$

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How do you condense $ln v + 4 ln w + \frac{ln u}{3}$ $lnv+4lnw+lnu/3$ ?

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