Question

How do you condense `lny-2ln(x-2)+3`?

Answer 1

`ln ((e^3y)/(x-2)^2)`

Explanation:

Exp and ln are inverse functions.`. ln (e^m)=m`.
So, `3 = ln (e^3)`.
`-2 ln (x-2)=ln((x-2)^(-2))`.
Use lna + ln b = ln c = ln (abc)
The given expression condenses to `ln ((e^3y)/(x-2)^2)`