How do you condense $log 2 ln 8 +5 ln z$ ?

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Answer 1 · 2017-07-20T06:50:46

$ln(root(ln10)(8^ln2)*z^5)$

We know that $logx=lnx/ln10$ so let's use this.

$log2ln8+5lnz=ln2/ln10*ln8+lnz^5=$

$ln8^(ln2/ln10)+lnz^5=ln(root(ln10)(8^ln2)*z^5)$

How do you condense log 2 ln 8 +5 ln zlog 2 ln 8 +5 ln z?