How do you condense $log x + log (x^2 - 196) - log 2 - log (x - 14)$ ?

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Answer 1 · 2016-03-29T15:11:25

$log(x+14)$

$log(x^2-196)=log(x^2-14^2)=log((x-14)*(x+14))$
$log x+log((x-14)(x+14))-log 2-log(x-14)$

$log x+cancel(log (x-14)) + log(x+14)-log 2-cancel(log(x-14))$

$log x+log(x+14)-log x$

$log(x*(x+14))-log x$

$log(x^2+14x)-log x$

$log((x^2+14x)/x)$

$log(x+14)$

How do you condense log x + log (x^2 - 196) - log 2 - log (x - 14)log x + log (x^2 - 196) - log 2 - log (x - 14)?