How do you condense $Log2r-2log4p+1/2log16x+2$ ?

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Answer 1 · 2016-07-26T18:59:20

$log[(50r x^(1/2))/p^2]$

Before we can condense all the terms, they all need to be log terms.
$Log2r-2log4p+1/2log16x+2$ ?
$2 = log100$
$Log2r-2log4p+1/2log16x+log 100$

Use the power law:

= $Log2r-log(4p)^2+log(16x)^(1/2)+log 100$

If logs are being added or subtracted, the numbers are being multiplied or divided.

= $log [(2r xx (16x)^(1/2) xx 100)/((4p)^2)]$

= $log [(200 r xx 4(x)^(1/2) )/(16p^2)]$

= $log[(50r x^(1/2))/p^2]$

How do you condense Log2r-2log4p+1/2log16x+2Log2r-2log4p+1/2log16x+2?