Question

How do you convert `1 + i sqrt(3)` to polar form?

Answer 1

`(2,pi/3)`

Explanation:

Using the formulae that link Cartesian to Polar coordinates.

`•r=sqrt(x^2+y^2)`

`•theta=tan^-1(y/x)`

here x = 1 and y`=sqrt3`

`rArrr=sqrt(1^2+(sqrt3)^2)=sqrt4=2`

and `theta=tan^-1(sqrt3)=pi/3`

Thus `(1,sqrt3)=(2,pi/3)" in polar form"`