How do you convert $-1-i$ to polar form?

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Answer 1 · 2016-09-19T11:39:26

Cartesian form: $(-1-i) rarr$ Polar form: $(sqrt(2),(5pi)/4)$

$(-1-i)$ is in Quadrant III with a reference angle of $pi/4$ and a distance from the origin (radius) of $sqrt(2)$
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How do you convert -1-i-1-i to polar form?