Question

How do you convert `2=(8x-y)^2-5y+7x` into polar form?

Answer 1

`(64x^2- 16xy+y^2)-5y+7x-2=0`
Now sub:
`x= rcostheta; y=rsin theta`
Noting that `r=x^2+y^2; theta=tan^-1 (y/x)`