Question

How do you convert `-3-3i` to polar form?

Answer 1

In polar form the equation is `Z=3sqrt2(cos 225 +isin225)`

Explanation:

Let `Z= -3 -3i ;` Modulas `Z: r =sqrt((-3)^2+(-3)^2)=3sqrt2`
Argument `Z; theta = 180^0 + tan^-1(3/3) = 180+45=225^0 (180^0` added as the point lies in 3rd quadrant). In polar form the equation is `Z=3sqrt2(cos 225 +isin225)`[Ans]