Question

How do you convert `3y= 2x^2-2x-7y^2` into a polar equation?

Answer 1

`7rsin^2theta-2rcos^2theta+2costheta+3sintheta=0`

Explanation:

`y=rsin (theta)` & `x=rcos (theta)`
`3r sin(theta)=2r^2cos^2(theta)-2rcos(theta)-7r^2sin^2(theta)`
`7r^2sin^2theta-2r^2cos^2theta+2rcostheta+3rsintheta=0`
`7rsin^2theta-2rcos^2theta+2costheta+3sintheta=0`