How do you convert $4-4i$ to polar form?

Question

20148 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-18T03:34:49

$4sqrt2 e^(i(7ou)/4)=4sqrt2(cos((7pi)/4)+i sin((7pi)/4))$

$x=4 and y=-4$ .
$x+i y=r (cos theta + i sin theta)$

$r=sqrt(x^2+y^2)=4 sqrt 2$ .

$cos theta=x/r=1/sqrt 2, sin theta=y/r=-1/sqrt2$

sine is negative and cosine is positive.
So, $theta$ is in the fourth quadrant,
$theta=2pi-pi/4=(7pi)/4$ .

How do you convert 4-4i4-4i to polar form?