How do you convert $((5, -4pi/3))$ into rectangular forms?

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Answer 1 · 2016-01-30T04:51:53

Rectangular coordinates are $x=-5/2$ and $y=(5sqrt3)/2$

Given: $r=5$ and $theta=(-4pi)/3=-240^@$
Angle $theta$ is located at the second quadrant.

$x=r cos theta=5*cos ((-4pi)/3)=-5/2$

$y=r sin theta=5*sin ((-4pi)/3)=(5sqrt3)/2$

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How do you convert ((5, -4pi/3))((5, -4pi/3)) into rectangular forms?