How do you convert $-5-5i$ to polar form?

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Answer 1 · 2018-05-19T16:10:17

$(5sqrt(2), pi/4)$

Polar form: $(r, theta)$

$a + bi$

$a = -5$
$b=-5$

$r = sqrt(a^2 + b^2) = sqrt((-5)^2 + (-5)^2) = sqrt(50)= 5sqrt(2)$

$theta = tan(b/a) = tan((-5)/-5) = tan(1) = pi/4$

$(5sqrt(2), pi/4)$

How do you convert -5-5i-5-5i to polar form?