How do you convert $5y= x -2xy$ into a polar equation?

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Answer 1 · 2018-05-13T11:32:41

$r=(costheta-5sintheta)/(sin(2theta))$

For this we will use the two equations:
$x=rcostheta$
$,y=rsintheta$

$5rsintheta=rcostheta-2(rcos theta)(rsintheta)$

$5rsintheta=rcostheta-2r^2costhetasintheta$

$5sintheta=costheta-2rcosthetasintheta$

$2rcosthetasintheta=costheta-5sintheta$

$r=(costheta-5sintheta)/(2costhetasintheta)$

$r=(costheta-5sintheta)/(sin(2theta))$

How do you convert 5y= x -2xy 5y= x -2xy into a polar equation?