How do you convert $[-6,3pi/2]$ to rectangular form?

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Answer 1 · 2016-07-10T04:46:42

Rectangular form is $(0,6)$

Polar coordinates are given as follows: $(r, theta)$ .

From the given problem, $r=-6, theta=(3pi)/2$

We can use the following formulas to get our x and y values:
$x = rcostheta, y=rsintheta$

$x = rcostheta = -6cos(3pi)/2 = -6 * 0 = 0$

$y = rsintheta = -6sin(3pi)/2 = -6 * -1 = 6$

Therefore, our coordinate is $(0,6)$

How do you convert [-6,3pi/2] [-6,3pi/2] to rectangular form?