Question

How do you convert `(6,9)` to polar form?

Answer 1

`(sqrt117 ,0.983)`

Explanation:

Using the formulae that links Cartesian and Polar coordinates.

`•r=sqrt(x^2+y^2)`

`•theta=tan^-1(y/x)`

here x = 6 and y = 9 : Substitute these values into the formulae.

`rArrr=sqrt(6^2+9^2)=sqrt117" in simplest form"`

and `theta=tan^-1(9/6)=0.983" radians"`

`rArr(r,theta)=(sqrt117,0.983)=(sqrt117,56.3^@)`