How do you convert $(6,-pi/5)$ into rectangular coordinates?

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Answer 1 · 2017-11-18T00:45:32

$approx (4.854, -3.527)$

In general to convert the polar coordinate $(r, theta)$ into rectangular coordinates, you just do $(rcostheta, rsintheta)$ .

In the case of $(6, -pi/5)$ , this would be
$(6cos(-pi/5), 6sin(-pi/5)) approx$ (4.854, -3.527)#

How do you convert (6,-pi/5)(6,-pi/5) into rectangular coordinates?