How do you convert $6 x + 3 y = 2$ $6 x+ 3 y = 2$ in polar form?

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How do you convert $6 x + 3 y = 2$ $6 x+ 3 y = 2$ in polar form?

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Answer 1 · 2015-12-24T12:47:26

$6 r cos (θ) + 3 r sin (θ) - 2 = 0$ $6rcos(theta) + 3rsin(theta) -2 = 0$

Explanation:

Substitute $x = r cos (θ)$ $x= rcos(theta)$ and $y = r sin (θ)$ $y = rsin(theta)$
$6 r cos (θ) + 3 r sin (θ) - 2 = 0$ $6rcos(theta) + 3rsin(theta) -2 = 0$

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How do you convert $6 x + 3 y = 2$ $6 x+ 3 y = 2$ in polar form?

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