Question

How do you convert `9=(x-7)^2+(y+4)^2` into polar form?

Answer 1

`r^2-14rcos theta+8rsintheta+56=0`

Explanation:

`9=x^2-14x+49+y^2+8y+16`->FOIL

`x^2+y^2 -14x +8y+(49+16-9)=0`

`x^2+y^2 -14x +8y+56=0`

Use these formulas:
`r^2=x^2+y^2, x=rcos theta, y=rsin theta`

`r^2-14rcos theta+8rsintheta+56=0`