Question

How do you convert `9x^3-2x-12y^2=8` into polar form?

Answer 1

`9r^3cos^3theta-2rcostheta-12r^2sin^2theta=8`

Explanation:

`x=rcostheta`
`y=rsintheta`

`9(rcostheta)^3-2(rcostheta)-12(rsintheta)^2=8`

`9r^3cos^3theta-2rcostheta-12r^2sin^2theta=8`