How do you convert $r=1+cos(theta)$ into cartesian form?

Question

19712 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-27T19:12:49

$x^2+y^2 = sqrt(x^2+y^2)+x$

Multiply both sides by $r$ :

$r^2 = r+rcos(theta)$

Now, since $r=sqrt(x^2+y^2)$ and $x=rcos(theta)$ , your equation becomes

$x^2+y^2 = sqrt(x^2+y^2)+x$

How do you convert r=1+cos(theta)r=1+cos(theta) into cartesian form?