How do you convert $r=2(cos(theta))^2$ into cartesian form?

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Answer 1 · 2016-02-27T05:38:34

It is $(x^2+y^2)^(3/2)=2x^2$

Hence $x=r*costheta$ and $y=r*sintheta$ we have that

$x^2+y^2=r^2=>r=sqrt(x^2+y^2)$

so

$r=2*(costheta)^2=>sqrt(x^2+y^2)=2*(x/r)^2=> r^2*(sqrt(x^2+y^2))=2x^2=> (x^2+y^2)^(3/2)=2x^2$

How do you convert r=2(cos(theta))^2r=2(cos(theta))^2 into cartesian form?