Question

How do you convert `r=2(cos(theta))^2` to rectangular form?

Answer 1

`=>(x^2+y^2)^3=4x^4`

Explanation:

Multiplying both sides by `r^2` we have
`r^3=2(rcostheta)^2`
Now `r=(x^2+y^2)^(1/2)` and `rcostheta= x`
So
`(x^2+y^2)^(3/2)=2x^2`
Squaring both sides
`=>(x^2+y^2)^3=4x^4` this is the rectangular form