Question

How do you convert `r = 3sin2θ` into rectangular form?

Answer 1

by putting `sintheta =y/r , cos theta = x/r and r =sqrt(x^2+y^2)`

Explanation:

we get,
given expression is
`r=3*2sintheta*costheta`
or, `r=3*2y/r*x/r`
or,`r^3=6xy`
or,`r^6=36x^2y^2`
or, `(x^2+y^2)^3=36x^2y^2` (putting,`r^2=x^2+y^2`)