How do you convert $r=6sin(theta)$ to rectangular form?

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Answer 1 · 2016-05-12T18:45:17

$x=6*cos(theta)sin(theta), y = 6*sin(theta)^2$

The pass equations are: $x=r *cos(theta),y=r *sin(theta)$ then substituting we get $x=6*cos(theta)*sin(theta), y = 6*sin(theta)^2$

How do you convert r=6sin(theta)r=6sin(theta) to rectangular form?