How do you convert $r = 7(1 - sin(θ))$ into rectangular form?

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Answer 1 · 2017-12-17T17:32:13

$(x^2+7y+y^2)^2=49x^2+49y^2$

$r=7*(1-sin(theta))$

$r=7-7sin(theta)$

$r^2=7r-7rsin(theta)$

After using $r=sqrt(x^2+y^2)$ , $r^2=x^2+y^2$ and $y=rsin(theta)$ inverse transforms,

$x^2+y^2=7sqrt(x^2+y^2)-7y$

$x^2+7y+y^2=7sqrt(x^2+y^2)$

$(x^2+7y+y^2)^2=49x^2+49y^2$

How do you convert r = 7(1 - sin(θ))r = 7(1 - sin(θ)) into rectangular form?