How do you convert $(sqrt3/2 ,1/2 )$ into polar coordinates?

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Answer 1 · 2018-07-09T05:49:30

$color(red)(r = 1, theta = (pi/6)^c " or " 30^@$

$(x,y) = (sqrt3/2, 1/2)$

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$r = sqrt(x^2 + y^2) = sqrt((sqrt3/2)^2 + (1/2)^2) = 1$

$theta = arctan ((1/2) / (sqrt3/2)) = (pi/6)^c " or " 30^@$

How do you convert (sqrt3/2 ,1/2 )(sqrt3/2 ,1/2 ) into polar coordinates?