Question

How do you convert `(sqrt3/2 ,1/2 )` into polar coordinates?

Answer 1

`color(red)(r = 1, theta = (pi/6)^c " or " 30^@`

Explanation:

`(x,y) = (sqrt3/2, 1/2)`

`r = sqrt(x^2 + y^2) = sqrt((sqrt3/2)^2 + (1/2)^2) = 1`

`theta = arctan ((1/2) / (sqrt3/2)) = (pi/6)^c " or " 30^@`