How do you convert cartesian $(-sqrt7, 0)$ to polar form?

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Answer 1 · 2016-04-27T14:42:04

Cartesian form $(x, y) = (-sqrt 7, 0) = (r cos theta, r sin theta)$ transforms to the polar form $(r, theta ) = ( sqrt 7, pi )$ .

$x=-sqrt 7 and y=0$ .

$r=sqrt(x^2+y^2)=sqrt 7. cos theta = x/r=-1 and sin theta =y/r=0$
So, $theta=pi$ ..

How do you convert cartesian (-sqrt7, 0)(-sqrt7, 0) to polar form?