How do you convert x^2 -4y^2 =4 to polar form?

1 Answer
Jul 8, 2016

r^2=4/(cos^2theta-4sin^2theta)

Explanation:

To convert from color(blue)"Cartesian to Polar form"

color(orange)"Reminder"

color(red)(|bar(ul(color(white)(a/a)color(black)(x=rcostheta,y=rsintheta)color(white)(a/a)|)))

rArrx^2-4y^2=4rArr(rcostheta)^2-4(rsintheta)^2=4

rArrr^2cos^2theta-4r^2sin^2theta=4

rArrr^2(cos^2theta-4sin^2theta)=4rArrr^2=4/(cos^2theta-4sin^2theta)