How do you convert $-xy=x+4y^2$ into a polar equation?

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Answer 1 · 2016-04-15T18:28:48

$4r^2sin^2theta+r^2costhetasintheta+rcostheta=0$

$-xy=x+4y^2$

Use equations $x=rcos theta,y=rsin theta$

$-rcos theta xx rsintheta=rcos theta+4r^2sin^2theta$

$-r^2costhetasintheta=rcostheta+4r^2sin^2theta$

$0=4r^2sin^2theta+r^2costhetasintheta+rcostheta$

How do you convert -xy=x+4y^2 -xy=x+4y^2 into a polar equation?