How do you convert $y = x^2$ to polar form?

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Answer 1 · 2016-06-23T11:39:48

$r = tan theta sec theta$

$x = r cos theta$
$y = r sin theta$

$r sin theta = (r cos theta)^2 = r^2 cos^2 theta$

$sin theta = r cos^2 theta$

$r = (sin theta)/(cos^2 theta) = tan theta sec theta$

How do you convert y = x^2 y = x^2 to polar form?