How do you cube a matrix $([2, -1], [3, 1])$ ?

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Answer 1 · 2018-07-30T09:09:55

The answer is $=((-7,-4),(12,-11))$

If you have a matrix $A$

The cube is

$=A^3=A^2*A$

Here,

$A=((2,-1),(3,1))$

Therefore,

$A^2=A*A=((2,-1),(3,1))*((2,-1),(3,1))$

$=((1,-3),(9,-2))$

$A^3=A^2*A=((1,-3),(9,-2))*((2,-1),(3,1))$

$=((-7,-4),(12,-11))$

How do you cube a matrix ([2, -1], [3, 1])([2, -1], [3, 1])?