Question

How do you determine p(c) given `p(x)=2x^2-x+1` and c=4?

Answer 1

`p(4)=27`

Explanation:

Express p(x) in terms of c.

That is : `p(color(blue)(c))=2color(blue)(c^2)-color(blue)(c)+1=2c^2-c+1`

now substitute c = 4 into p(c)

`p(color(red)(4))=2(color(red)(4^2))-color(red)(4)+1`

`rArrp(4)=32-4+1=27`