Question

How do you determine p(c) given `p(x)=8x^3+12x^2+6x+1` and c=-1/2?

Answer 1

0

Explanation:

The first step is to obtain p(c). To do this substitute x = c into p(x).

`p(color(blue)(c))=8(color(blue)(c))^3+12(color(blue)(c))^2+6(color(blue)(c))+1=8c^3+12c^2+6c+1`

We now have to evaluate p(c) when c `=-1/2`

`p(color(red)(-1/2))=8(color(red)(-1/2))^3+12(color(red)(-1/2))^2+6(color(red)(-1/2))+1`

`rArrp(-1/2)=-1+3-3+1=0`