How do you determine p(c) given $p(x)=x^4-2x^2+4$ and c=3/2?

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Answer 1 · 2016-10-09T15:38:23

$73/16$

$p(c)=(3/2)^4-2(3/2)^2+4$
$p(c)=(81/16)-2(9/4)+4$
$p(c)=(81/16)-(72/16)+(64/16)$
$p(c)=73/16$

How do you determine p(c) given p(x)=x^4-2x^2+4p(x)=x^4-2x^2+4 and c=3/2?