How do you determine the quadrant in which the angle $- 260^{\circ}$ $-260^circ$ lies?

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How do you determine the quadrant in which the angle $- 260^{\circ}$ $-260^circ$ lies?

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Answer 1 · 2016-12-16T15:13:34

Quadrant II

Explanation:

The co-terminal angle of (-260^@) is:
360 - 260 = 100^@
There for, the angle (-260^@) lies in Quadrant II (From $90^{\circ} \to 180^{\circ}$ $90^@ to 180^@$ )

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How do you determine the quadrant in which the angle $- 260^{\circ}$ $-260^circ$ lies?

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How do you determine the quadrant in which the angle $- 260^{\circ}$ $-260^circ$ lies?