How do you determine which is greater $5^{2} \cdot 5^{6} (\Leftrightarrow) 5^{7}$ $5^2*5^6 (<=>) 5^7$ ?

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Answer 1 · 2015-10-01T17:24:32

It is $5^{2} \cdot 5^{6} = 5^{2 + 6} = 5^{8} > 5^{7}$ $5^2*5^6=5^(2+6)=5^8>5^7$ Hence we have that

$5^{2} \cdot 5^{6} > 5^{7}$ $5^2*5^6>5^7$

How do you determine which is greater 5^2*5^6 (<=>) 5^752⋅56(⇔)575^2*5^6 (<=>) 5^7?