How do you determine which is greater ${(6^{2})}^{2} (\Leftrightarrow) 3^{4} \cdot 2^{4}$ $(6^2)^2 (<=>) 3^4*2^4$ ?

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Answer 1 · 2015-09-28T02:08:30

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For ${(6^{2})}^{2} = 6^{4} = {(3 \cdot 2)}^{4} = 3^{4} \cdot 2^{4}$ $(6^2)^2=6^4=(3*2)^4=3^4*2^4$ so they are equal

How do you determine which is greater (6^2)^2 (<=>) 3^4*2^4(62)2(⇔)34⋅24(6^2)^2 (<=>) 3^4*2^4?